F(x)=x^2+5x+100

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Solution for F(x)=x^2+5x+100 equation: 



(F)=F^2+5F+100

We move all terms to the left:

(F)-(F^2+5F+100)=0

We get rid of parentheses

-F^2+F-5F-100=0

We add all the numbers together, and all the variables

-1F^2-4F-100=0

a = -1; b = -4; c = -100;
Δ = b2-4ac
Δ = -42-4·(-1)·(-100)
Δ = -384
Delta is less than zero, so there is no solution for the equation

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